American Fraternal Alliance - USA trade association of fraternities. Article “American Fraternal Alliance” in English Wikipedia has 37.1 points for quality (as of July 1, 2026). The article contains 16 references and 7 sections.
Since the creation of article “American Fraternal Alliance”, its content was written by 18 registered users of English Wikipedia and edited by 18 registered Wikipedia users in all languages.
The article is cited 20 times in English Wikipedia and cited 20 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2026 (including revision history and pageviews for previous years).
| Best Rank | English: #1485013 04.2015 |
Global: #2566051 04.2015 |
| Best Rank | English: #101892 09.2019 |
Global: #344504 09.2019 |
On 1 July 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 2026 FIFA World Cup, Kylian Mbappé, Erling Haaland, Democratic Republic of the Congo, FIFA World Cup, Harry Kane, Romelu Lukaku, Senegal, Michael Olise, Sadio Mané.
In English Wikipedia the most popular articles on that day were: 2026 FIFA World Cup, Harry Kane, Julián Quiñones, List of FIFA World Cup top goalscorers, Kylian Mbappé, Democratic Republic of the Congo, Erling Haaland, DR Congo national football team, Melat Kiros, FIFA World Cup.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 50 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2026. When calculating current popularity and AI of articles data from June 2026 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2026... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(14.08+12.8+14.29+50+94.18)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
